Question

Daca x, y, z e N, x×y=96,x×z=80, atunci y+z/y-z este egal cu?

Answer 1

x*y=96
x*z=80
                (+)
x*y+x*z=96+80
x(y+z)=176⇒y+z=176/x

acum scadem cele 2 relatii si obtinem: x*y-x*z=96-80
                                                         x(y-z)=16⇒y-z=16/x

(y+z)/(y-z)=$\frac{ \frac{176}{x} }{ \frac{16}{x} } = \frac{176}{x} * \frac{x}{16}= \frac{176}{16} =11$