Question

Dacau a/2 = b/3 ; b/4 = c/5 ; c/6 = d/7 si a+b+c+d = 20 aflati a b c d

Answer 1

a/2 = b/3 deci b=3a/2

b/4=c/5 deci c=5b/4 deci c=15a/8

c/6=d/7 deci d=7c/6 deci d=105a/48

a+b+c+d=20 deci a+ 3a/2 + 15a/8 + 105a/48

Aducem la acelasi numitor adica 48:

(48a + 72a + 90a + 105a)/48 = 20

315a = 960 => a=960/315=64/21

b=32/7

c=40/7

d=20/3