Question

dar daca trebuie sa aflam :
$2* z^{2}+z+2=0$

Answer 1

Δ = 1 - 4·2·2 = 1 - 16 =  -15 = 15 · ( - 1  ) = 15i²
z₁ =( -1 - i√15 )  / 4 

z₂ = ( - 1 +i√15 )  / 4

Answer 2

[tex]2z^2+z+2=0 \\ \Delta=b^2-4ac=1-4*2*2=1-16=-15=15i^2 \\ z_1= \frac{-b- \sqrt{\Delta} }{2a}= \frac{-1- \sqrt{15i^2} }{4}= \frac{-1-i \sqrt{15} }{4} \\ z_2= \frac{-b+ \sqrt{\Delta} }{2a}= \frac{-1+ \sqrt{15i^2} }{4}= \frac{-1+i \sqrt{15} }{4} [/tex]
Daca rezolvarea este in numere complexe C atunci solutiile sunt aeste.
Dar daca in numere reale R atunci solutia e vida