Question

dau coroana...........​

Answer 1

Răspuns:

Explicație pas cu pas:

a) x = 3√8-4√50-√27

x = 6√2-20√2-3√3

x = -14√2-3√3

y = 3√48-√98-2√75

y = 12√3-7√2-10√3

y = 2√3-7√2

x+y = -14√2-3√3+2√3-7√2 = -21√2-3√3+2√3 =

= -21√2-√3.

y-x = 2√3-7√2-(-14√2)-3√3 = 2√3-7√2+14√2-3√3 = -√3+7√2.

b) x = 5√8-√20-4√45

x = 10√2-2√5-12√5

x = 10√2-14√5

y = 7√18-√125-3√98

y = 21√2-√125-21√2

y = -√125 = -5√5

x+y = 10√2-14√5+(-5√5) = 10√2-14√5-5√5 = 10√2-19√5.

y-x = -5√5-10√2-14√5 = -19√5-10√2.

Answer 2

Răspuns:

$a)x = \sqrt{8} - 4 \sqrt{50} - \sqrt{27} = 2 \sqrt{2} - 20 \sqrt{2} - 3 \sqrt{3 } = \\ - 18 \sqrt{2} - 3 \sqrt{3}$

$y = 3 \sqrt{48} - \sqrt{98} - 2 \sqrt{75} = 12 \sqrt{3} - 21\sqrt{2 } - 10 \sqrt{3} = \\ 2 \sqrt{3 } -21 \sqrt{2}$

$x + y = - 39\sqrt{3} - 25 \sqrt{2} \\ y - x = 5 \sqrt{3} + 11 \sqrt{2}$

$b)x = 5 \sqrt{8} - \sqrt{20} - 4 \sqrt{45} = 10 \sqrt{2} - 2 \sqrt{5} - 12 \sqrt{5} = 10 \sqrt{2} - 14 \sqrt{5}$

$y = 7 \sqrt{18} - \sqrt{125} - 3 \sqrt{98} = 21 \sqrt{2} - 5 \sqrt{5} - 21\sqrt{2} = \\ 14 \sqrt{2 } - 5 \sqrt{5}$

$x + y = 24 \sqrt{2} - 19 \sqrt{5} \\ y - x = 4 \sqrt{2} + 9 \sqrt{5}$