Question

dau coroana care rasp cel mai rpdd​

Answer 1

A={x∈ℝ / |2x+1| ≤5}

|2x+1| ≤5

=> -5 ≤2x+1 ≤ 5 /-1

-6≤ 2x≤ 4/:2

-3 ≤x ≤2

x∈ℝ => A=[-3;2]

B={x∈ℝ / -3<(x+1)/2 ≤ 1}

-3<(x+1)/2 ≤ 1 /×2

-6<x+1≤2 /-1

-7<x ≤1

x∈ℝ => B=(-7;1]

A∩B=[-3;-1]

A\B=(1;2]

B\A=(-7;-3)