Question

dau coroana! e Urgent!!!​

Answer 1

Răspuns:

Explicație pas cu pas:

99^51

u(99^51) = u(9^51) = 9

u(9^1) = 9

u(9^2) = 1

u(9^3) = 9

9 la putere impara se termina in 9

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11^53 + 15^53 + 17^53

u(11^53) = u(1^53) = 1

1 la orice putere este 1

u(15^53) = u(5^53) = 5

5 la orice putere se termina in 5

u(17^53) = u(7^53) = 7

u(7^1) = 7

u(7^2) = 9

u(7^3) = 3

u(7^4) = 1

u(7^5) = 7

ultima cifra se repeta din 4 in 4

53 : 4 = 13 rest 1 (13 grupe de 4 si incepe inca o grupa)

u(11^53 + 15^53 + 17^53) = u(1 + 5 + 7) = u(13) = 3

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313^100

u(313^100) = u(3^100) = 1

u(3^1) = 3

u(3^2) = 9

u(3^3) = 7

u(3^4) = 1

u(3^5) = 3

ultima cifra se repeta din 4 in 4

100 : 4 = 25 rest 0 (25 grupe de 4)

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68^86

u(68^86) = u(8^86) = 4

u(8^1) = 8

u(8^2) = 4

u(8^3) = 2

u(8^4) = 6

u(8^5) = 8

ultima cifra se repeta din 4 in 4

86 : 4 = 21 rest 2

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f) Succes la calcule!