Question

!
!

DAU COROANA!
EXERCITIUL 4!!

Answer 1

Răspuns:

a) $\frac{2x7+1}{7} + \frac{7x1+3}{7}$= $\frac{15}{7} +\frac{10}{7} =$$\frac{15+10}{7}$=$\frac{25}{7}$= 3 $\frac{4}{7}$ ( adica 3 intregi si 4/7)

b) $\frac{5*1+2}{5}$ + $\frac{3*10+1}{10}$= $\frac{7}{5} + \frac{31}{10}$  = $\frac{7*2+ 31}{10}$= $\frac{14+31}{10} = \frac{45}{10}$= 4$\frac{5}{10}$ ( adica 4 intregi si 5/10)

c) $\frac{3*3+1}{3} + \frac{5*2+2}{5}$= $\frac{10}{3} + \frac{12}{5}$= $\frac{5*10+ 12*3}{15} =\frac{50+36}{15}$= $\frac{86}{15} =$ 5 $\frac{11}{15}$

e) $\frac{5*6+ 5}{6} - \frac{1*6+1}{6}$= $\frac{35}{6} - \frac{7}{6}$= $\frac{35-7}{6} = \frac{28}{6}$= 4 $\frac{4}{6}$

f) $\frac{4*18+ 5}{18} - \frac{3*9+1}{9}$= $\frac{77}{18} - \frac{28}{9}$= $\frac{77}{18} - \frac{28*2}{18}$= $\frac{77- 56}{18}$= $\frac{21}{18}$= 1 $\frac{3}{18}$

g)$\frac{7*7+1}{7} - \frac{4*3+2}{3} = \frac{50}{7} - \frac{14}{3}$= $\frac{3*50- 14*7}{21}$= $\frac{150- 98}{21}$=$\frac{52}{21}$= 2 $\frac{10}{21}$

h) $\frac{9*3+2}{3} - \frac{8*4+1}{4}$= $\frac{29}{3} - \frac{33}{4}$= $\frac{29*4- 33*3}{12}$= $\frac{116- 99}{12}$= $\frac{17}{12}$= 1 $\frac{5}{12}$