Question

dau coroana!!!!! pls​

Answer 1

Răspuns:

.........................................

Answer 2

$\Big(\sqrt{3} +\sqrt{2} \Big)\cdot \Big(2\sqrt{2} +\sqrt{3} \Big)\cdot \Big(\sqrt{3} -2\sqrt{3} \Big)=\\\\=\Big(\sqrt{3}\cdot 2\sqrt{2} +\sqrt{3} \cdot \sqrt{3} +\sqrt{2}\cdot 2\sqrt{2} +\sqrt{2} \cdot \sqrt{3} \Big)\cdot \Big(\sqrt{3} -2\sqrt{3} \Big)=\\\\=\Big(2\sqrt{6} +3+2 \cdot 2+\sqrt{6}\Big)\cdot \Big(\sqrt{3} -2\sqrt{3} \Big)=\Big(3\sqrt{6} +7\Big)\cdot \Big(\sqrt{3} -2\sqrt{3}\Big)=$

$= 3\sqrt{6} \cdot \sqrt{3} -3\sqrt{6} \cdot 2\sqrt{3} +7 \cdot \sqrt{3}-7\cdot 2\sqrt{3} =3\sqrt{18} -6\sqrt{18} +7\sqrt{3} -14\sqrt{3} =\\\\=3 \cdot 3\sqrt{2} -6 \cdot 3\sqrt{2} +7\sqrt{3} -14\sqrt{3}=9\sqrt{2} -18\sqrt{2} +7\sqrt{3} -14\sqrt{3} =\\\\=\boxed{-9\sqrt{2}-7\sqrt{3} }$