Question

Dau coroana pt acest exercitiu si mult respect celui care ma ajuta
(3x-4)•3x+4)-(2x-3)^2=5•(x-1)^2+3

Answer 1

(3x - 4) • (3x + 4) - (2x - 3)² = 5 • (x-1)² + 3

-(2x -3)² + (3x)² + 3x•4 - 4•3x - 16 = 5(x - 1)² + 3
3²x² + -(2x)² - 2•2x • (-3) - (-3)² + 12x - 16 = 5(x²+2x•(-1) + (-1)²) + 3
9x² - 9 - 2²x² - (-12)x - 16 = 5(1 + x² + (-2)x) + 3
-4x² + 9x² + 12x - 25 = 5(x² - 2x + 1) + 3
5x² + 12x - 25 = 5x² - 5•2x + 5 + 3
5x² + 12x = 5x² - 10x + 33
5x² + 12x - 25 + 25 = 5x² - 10x + 8 + 25
12x = -10x + 33
5x² + 12x - 5x² = 5x² - 5x² - 10x + 33
22x = 33
x = 3 / 2.