Question

dau coroana urgent si corect va rog frumos​

Answer 1

$\log _5x=\log _5\frac{1}{4}-2\log _5 \frac{2}{3}+\log _5\frac{4}{9}\\ \\ \log _5 x=\log _5\frac{1}{4}-\log _5 (\frac{2}{3})^2+\log _5 \frac{4}{9}\\ \\ \log _5 x =\log _ 5\frac{1}{4} - \log _5 \frac{4}{9}+\log _5 \frac{4}{9}\\ \\ \log _5x=\log _5 \frac{1}{4}\\ \\ \Rightarrow \boxed{x=\frac{1}{4}}$