Question

dau coronița! Va roggggg​

Answer 1

Bună!

$(8 {}^{x} \times 4 {}^{3}) {}^{2} \div 16 {}^{3} = 64 \\ (8 {}^{x} \times 4 {}^{3}) {}^{2} \div 2 {}^{12} = 2 {}^{6} \\ \frac{(8 {}^{x} \times 4 {}^{3}) {}^{2}}{2 {}^{12} } =2 {}^{6} \\ \frac{(2 {}^{3x} \times 2 {}^{6}) {}^{2} }{2 {}^{12} } = 2 {}^{6} \\ \frac{(2 {}^{3x + 6}) {}^{2} }{2 {}^{12} } = 2 {}^{6} \\ \frac{2 {}^{6x + 12} }{2 {}^{12} } = 2 {}^{6} \\ 2 {}^{6x} = 2 {}^{6} \\ 6x = 6 \\ x = 6 \div 6 \\ x = 1$