Question

DAU Si CORONITA !! repede pls

Answer 1

a)În ΔCBA, m(∡B)=90°, din Teorema lui Pitagora=>
AC²=BC²+AB²
BC²=AC²-AB²
BC²=289 cm-225 cm²
BC²=64 cm²
BC=√64 cm
BC=8 cm
b) AABCD=L*l=AB*BC=15 cm*8 cm=120 cm²
PABCD=2(L+L)=2(AB+BC)=2(15 cm+8 cm)=2*23 cm=46 cm
c) x/100*L=l
x/100*15 cm=8 cm
x=8 cm/15 cm*100
x=8*20/3
x=160/3
x=53,(3)%