Question

De rezolvat in C ecuatia : (1+i)z=3-i

Answer 1

Not z=a+bi
(1+i)(a+bi)=3-i
a+bi+ai-b=3-i
a-b+i(a+b)=3-i

a-b=3
a+b=-1

rezulta a=1 si b=-2

Answer 2

$z= \frac{3-i}{1+i}$
$z= \frac{(3-i)(1-i)}{(1+i)(1-i)}$
$z= \frac{3-i-3i+ i^{2} }{1- i^{2} }$
$z= \frac{2-4i}{2}$
$z=1-2i$