Question

de scris formule moleculare si denumitile a cite 5 substante din fiecare clasa

Answer 1

Acizi:

HCl - acid clorhidric   => MHCl = AH + ACl = 1+35,5=36,5g/mol

HNO3 - acid azotic => MHNO3 = AH + AN + 3AO = 1+14+3*16=63g/mol

H2SO4 - acid sulfuric => MH2SO4 = 2AH + AS + 4AO = 2*1+32+4*16=98g/mol

H3PO4 -  acid fosforic => MH3PO4 = 3AH + AP + 4AO = 3*1+31+16*4=98g/mol

HCN - acid cianhidric => MHCN = AH + AC + AN = 1+12+14=27g/mol

Baze:

NaOH - hidroxid de sodiu (soda caustica) => MNaOH = ANa+AO+AH=23+16+1=40g/mol

Ca(OH)2 - hidroxid de calciu => MCa(OH)2 = ACa+2(AO+AH) = 40+2(16+1)=74g/mol

KOH - hidroxid de potasiu => MKOH=AK+AO+AH=39+16+1=56g/mol

Mg(OH)2 - hidroxid de magneziu => MMg(OH)2 = AMg+2(AO+AH)=24+2(16+1)=24+34=58g/mol

Ba(OH)2 - hidroxid de baiu => MBa(OH)2 = ABa+2*17=137+37=174g/mol

Saruri:

NaCl - clorura de sodiu (sarea de bucatarie) => MNaCl = ANa+ACl=23+35,5=58,5g/mol

CuCl2 - clorura de cupru => MCuCl2 = ACu + 2ACl => 64+71=135g/mol

MgCl2 - clorura de magneziu => MMgCl2= AMg+2ACl = 24+71=95g/mol

CuSO4 - sulfat de cupru => MCuSO4 = ACu+AS+4AO=64+32+64=128+32=160g/mol

BaSO4 - sulfat de bariu => MBaSO4 = ABa+AS+4AO=137+32+64=169+64=233g/mol

Oxizi:

CaO - oxid de calciu (var nestins) => MCaO=ACa+AO=40+16=56g/mol

Al2O3 - oxid de aluminiu => MAl2O3 = 2AAl + 3AO = 54+48=102g/mol

Fe2O3 - oxid de fier => MFe2O3 = 2AFe+3AO = 2*56+48=160g/mol

BaO - oxid de bariu => MBaO = ABa+AO=137+16=153g/mol

MCuO - oxid de cupru => MCuO = ACu + AO =64+16=80g/mol