Question

Demonstrati ca numarul abc +bca+cab se divide cu 37.

Answer 1

ax100+bx10+c+100b+10c+a+100c+10a+b=100(a+b+c)+10(a+b+c)+(a+b+c)=(a+b+c)(100+10+1)=(a+b+c)111 se divide 37=3(a+b+c)
111:37=3