Question

descompumeti in factori ireductibili:

1. x²-5x-6
2. 3x²-10x+3​

Answer 1

Explicație pas cu pas:

${x}^{2} - Sx + P = 0$

$S = x_1+x_2 \\ P = x_1x_2$

1.

$x²-5x-6 = {x}^{2} - 6x + x - 6 = x(x - 6) + (x - 6) = (x - 6)(x + 1)$

2.

$3x²-10x+3 = 3 {x}^{2} - x - 9x + 3 = x(3x - 1) - 3(3x - 1) = (3x - 1)(x - 3)$

Answer 2

1) x² - 5x - 6 = x² + x-6x - 6 = x(x+1) - 6(x+1) = (x+1)(x-6)

2) 3x² - 10x + 3 = 3x² -x-9x + 3 = x(3x-1) - 3(3x-1) = (3x-1)(x-3)