Question

descompune in factori
(x la puterea2+x)(x la puterea2+x-8)+12
​

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

Răspuns:

(x²+x)(x²+x-8)+12=(x-1)(x+3)(x-2)(x+2)

Explicație pas cu pas:

(x²+x)(x²+x-8)+12=

=x⁴+x³-8x²+x³+x²-8x+12

=x⁴+2x³-7x²-8x+12

=x⁴-x³+3x³-3x²-4x²+4x-12x+12

=x³(x-1)+3x²(x-1)-4x(x-1)-12(x-1)

=(x-1)(x³+3x²-4x-12)

=(x-1)[x²(x+3)-4(x+3)]

=(x-1)(x+3)(x²-4)

=(x-1)(x+3)(x-2)(x+2)