Question

descompune in produs de puteri de numere prime următoarele numere :
a) 12,24,60,75
b) 120,576,324,800
c) 2475,4410,12100,19008

REPEDEE DAU COROANAAA !!!!!!​

Answer 1

Răspuns:

12 2

6 2

3 3

1 - => 12=2laputerea2 + 3

24 2

12 2

6 2

3 3

1 - => 24= 2laputerea3 × 3

60 2×5

6 2

3 3

1 - => 60= 2laputerea2 ×5×3

Answer 2

$12 = 2 {}^{2} \times 3 \\ 24 = 3 \times 2 {}^{3} \\ 60 = 3 \times 5 \times 2 {}^{2} \\ 75 = 5 \times 5 \times 3 \\ 120 = 3 \times 5 \times 2 {}^{2} \\ 576 = 3 {}^{2} \times 2 {}^{6} \\ 324 = 2 {}^{2} \times 2 {}^{4} \\ 800 = 2 {}^{5} \times 5 {}^{2} \\ 2475 = 3 {}^{2} \times 5 {}^{2} \times 11 \\ 4410 = 2 \times 3 {}^{2} \times 5 \times 7 {}^{2} \\ 12100 = 2 {}^{2} \times 5 {}^{2} \times 11 {}^{2} \\ 19008 = 2 {}^{6} \times 3 {}^{3} \times 11$