Question

Descompuneri:
a)x²-1=
b)x²-49=
c)16-81x(la a 4-a)=
d)(x+1)²-1=


a)x²+3x+2=
b)x²+5x+6+
c)x²-10x+16=
d)x²+x-2=

Answer 1

 a)x²-1=(x-1)(x+1)
b)x²-49=(x-7)(x+7)
c)16-81 x⁴=(4-9x²)(4+9x²)
d)(x+1)²-1=(x+1+1)(x+1-1)=(x+2)x

a)x²+3x+2=x(x+3)+2
b)x²+5x+6=x(x+5)+6
c)x²-10x-16=x(x+10)16
d)x²+x-2=x(x+1)-2
Aici dam factor comun doar din primi doi termeni.
Succes!!

Answer 2

a) x²-1=> x²-1²=> (x-1)(x+1)
b)x²-49=>x²-7²=>(x-7)(x+7)
c) 81x⁴ sau (81x)⁴??
d) (x+1)²-1=> (x+1)²-1²=> [(x+1)-1][(x+1)+1]

a) x²+x+2x+2= x(x+1) +2(x+1)=(x+1)(x+2)
b)x²+2x+3x+6=x(x+2)+3(x+2)=(x+2)(x+3)