Question

Descompuneti:
3x la put 2 -1
25 a la put 2 -2
5x la put 2 -3
1/2-16 a la put 2
2. Calculati:
(2-3x)(2+3x)
( x la put 2 +3 ) ( x la put 2-3, )
(x-1)(x+1)(x la put 2 +1)
3. Calculati
(√5+√3)(√5-√3)
(1-√6)(1+√6)
(4√5+2)(4√5-2)

Answer 1

3x² -1 = ( √3x -1) ( √3x+1)
( 25a)² -2 = ( 5a- √2) ( 5a+√2)
(5x)²-3 = ( 5x - √3) ( 5x +√30
1/2 - (16 a)² = ( √2 /2 - 4a) ) (√2/2 +4a)
2.
( 2-3x) ( 2+3x)= 2² - (3x)²=4 - 9x²
( x²+3) ( x² -3) =( x²)² - 3²= x⁴ -9
( x -1) ( x+1) ( x² +1) = ( x² -1) ( x² +1) = x⁴ -1

3  formula        (x-y) ( x+y) = x² -y²
(√5 +√3 ) ( √5 -√3 )= ( √5)² - (√3)² = 5-3=2
( 1 -√6) ( 1+√6) = 1² - (√6)²= 1-6=-5
( 4√5 +2 ) ( 4√5 - 2 ) = ( 4√5)² -2² = 80 -4 =76