Question

descompuneti in factori:​

Answer 1

Explicație pas cu pas:

f)

(x-3)²-25 = (x-3)²-5² = (x-3-5)(x-3+5) = (x-8)(x+2)

g)

x²-3x-10 = x²-5x+2x-10 = x(x-5) + 2(x-5) = (x-5)(x+2)

h)

2x²-9x+7 = 2x²-2x-7x+7 = 2x(x-1) -7(x-1) = (2x-7)(x-1)

i)

(4x+1)²-(2x+3)² = (4x+1-2x-3)(4x+1+2x+3) = (2x-2)(6x+4) =4(x-1)(3x+2)

Answer 2

Răspuns:

f. (x-3)²-25=x²+6x+9-25= x²+6x-16=x²-2x+8x-16=x(x-2)+8(x-2)=(x-2)(x+8)

g.x²-3x-10=(x-5)(x+2)

h. 2x²-9x+7=(2x-7)(x-1)

i. (4x+1)²-(2x+3)²=

(4x+1+2x+3)(4x+1-2x-3)=

(6x+4)(2x-2)=

2(3x+2)·2(x-1)=

4(3x+2)(x−1)