Question

Descompuneti in factori :
a) x^2+3x-4 e)x^2-3x-4 i)x^2+2x-24
b)x^2+5x-14 f)x^2+5x-14 j)x^2+2x-48
c)x^2-10x-11 g)x^2-7x-18 k)x^2-5x-50
d)x^2-x-14 h)x^2-2x-15 L)x^2+2x-35

Answer 1

Explicație pas cu pas:

a)x²+3x-4 = x²-x+4x-4 = x(x-1)+4(x-1) =

=(x-1)(x+4)

e)x²-3x-4 = x²+x-4x-4 = x(x+1)-4(x+1) =

=(x+1)(x-4)

i)x²+2x-24 = x²-4x+6x-24 = x(x-4)+6(x-4) =

= (x-4)(x+6)

b)x²+5x-14 = x²-2x+7x-14 = x(x-2)+7(x-2) =

= (x-2)(x+7)

j)x²+2x-48 = x²-6x+8x-48 = x(x-6)+8(x-6) =

= (x-6)(x+8)

c)x²-10x-11 = x²+x-11x-11 = x(x+1)-11(x+1) =

= (x+1)(x-11)

g)x²-7x-18 = x²+2x-9x-18 = x(x+2)-9(x+2) =

= (x+2)(x-9)

k)x²-5x-50 = x²+5x-10x-50 = x(x+5)-10(x+5) =

= (x+5)(x-10)

h)x²-2x-15 = x²+3x-5x-15 = x(x+3)-5(x+3) =

= (x+3)(x-5)

L)x²+2x-35 = x²+7x-5x-35 = x(x+7)-5(x+7) =

= (x+7)(x-5)