Question

Descompuneți în factori:
a).x²+5x+6
b).x²+7x+10
c).x²+9x+20
d).x²+8x+15
e).x²+9x+14

Answer 1

a)x²+5x+6 =x²+2x+3x+6 =x(x+2)+3(x+2)=(x+2)(x+3)
b)x²+7x+10=x²+2x+5x+10 =x(x+2)+5(x+2)=(x+2)(x+5)
c)x²+9x+20=x²+4x+5x+20 =x(x+4)+5(x+4)=(x+4)(x+5)
d)x²+8x+15=x²+3x+5x+15 =x(x+3)+5(x+3)=(x+3)(x+5)
e)x²+9x+14=x²+2x+7x+14 =x(x+2)+7(x+2)=(x+2)(x+7)