Question

descompuneti in factori:
x la patrat + 4x -5
x la patrat +7x - 8
x la patrat +x-2
x la patrat + 4x -12
x la patrat + 2x -15
x la patrat + 3x - 10



dau coroanaaaaaaa

Answer 1

Sunt foarte usoare. O sa vina asa:

x la a 2 + 4x-5= x la 2 + 5x-x-5= x(x+5) -(x-5) =
(la a doua paranteza schimbam semnul adica in loc de minus punem plus) = x(x-5)-(x+5)= (x+5)(x-1).

x la 2 +7x -8= x la 2 + 8x-x - 8= x(x+8)-(x-8)=
(x+8)(x-1).

x la 2 + x-2= x la 2 + 2x-x -2= x(x+2) -(x-2)=
(x+2)(x-1).

x la 2 +4x- 12= x la 2 + 6x-2x-12= x(x+6)-2(x-6)=
(x+6)(x-2).

x la 2 + 2x- 15= x la 2 + 5x-3x-15= x(x+5)-3(x-5)=
(x+5)(x-3).

x la 2 + 3x- 10= x la 2 + 5x-2x-10=x(x+5)-2(x-5)=
(x+5)(x-2).