Question

descompuneti in factorii
3x^2+4x-7
3x^2+11+8

Answer 1

3x²+4x-7 = 3x²-3x + 7x-7 = 3x(x-1) +7(x-1)

= (x-1)(3x+7)

3x²+11x+8 = 3x²+3x +8x+8

3x(x+1) +8(x+1)

(x+1)(3x+8)