Question

descoperă valorile pentru a,b şi c ştiind că a+b+c=78 b:a=2 rest 2 c:b=2 rest 2

Answer 1

a+b+c=78
b:a=2 rest 2 ⇒b=2a+2
c:b=2 rest 2 ⇒c=2b+2=2(2a+2)+2

inlocuim
a+2a+2+2(2a+2)+2=78
a+2a+2+4a+4+2=78
7a+8=78
7a=70
a=10
b=2*10+2=22
c=2*22+2=46

Answer 2

a+b+c=78
b:a=2r2⇒b=2a+2
c:b=2r2⇒c=2b+2⇒c=2(2a+2)+2⇒c=4a+4+2⇒c=4a+6
a+2a+2+4a+6=78
7a+8=78
7a=78-8
7a=70
a=70:7
a=10
b=2x10+2
b=22
c=4x10+6
c=46
V:10+22+46=78