Question

det:(3x-1)^2=9
repede va rog​

Answer 1

Răspuns:

(3x-1)²=9

9x²-6x+1=9

9x²-6x+1-9=0

9x²-6x-8=0

==> ∆=b²-4ac=(-6)²-4•9•(-8)=324

X1,2=-b±√∆/2a

X1=-b-√∆/2a=6-√324/2•9=6-18/18= -2/3

X2=-b+√∆/2a=6+√324/2•9=6+18/18=24/18=8/6=4/3

Answer 2

Răspuns:

Explicație pas cu pas:

$\bf (3x-1)^2=9$

$\bf (3x-1)^2=3^{2}\implies 3x-1 = 3$

$\bf 3x = 3 +1$

$\bf 3x = 4$

$\boxed{\bf x =\dfrac{4}{3} }$