Question

Determimati cel mai mic numar natural care impartit pa rand la 24 ,48 si 40 da de fiecare data restul 17 ai caturi nenule.

Answer 1

x=24c+17     ⇒x-17=24c
x=48c+17       ⇒x-17=48c
x=40c+17     ⇒x-17=40c

x-17∈M[24,48,40}
[24,48,40]=2⁴x3x5=240
M240={240, 480,....}

x-17=240
x=240+17
x=257
257:24=10 rest 17
257:48=5 rest 17
257:40=6 rest 17
deci nr.257 este cel mai mic nr.care indeplineste toate conditiile