Question

determina cele 3 nr.a b c stiind ca: a+b+c=905 b:a=3rest3 c:b=20rest10

Answer 1

a+b+c=905
b:a=3rest3⇒b=3*a+3
c:b=20rest10⇒c=20*b+10
c=20(3a+3)+10
c=60a+60+10
c=60a+70
a+3a+3+60a+70=905
64a+73=905
64a=905-73
64a=832
a=832:64
a=13
b=3*13+3
b=42
c=60*13+70
c=850
V:13+42+850=905