Question

determina cele trei nu a,b si c stiind ca : a+b+c=111 b:a=3rest3 c:b=2rest 2​

Answer 1

Răspuns:

a+b+c=111

b:a=3 rest 3=>b=3a+3

c:b=2 rest2=>c=2b+2=>c=2(3a+3)+2=>c=6a+8

a+3a+3+6a+8=111

10a=111-11

a=100:10=>a=10

b=3·10+3=33

c=6·10+8=68

Answer 2

a + b + c = 111

b : a = 3 rest 3

c : b = 2 rest 2

b = 3 × a + 3

c = 2 × b + 2

c = 2 × ( 3 × a + 3 ) + 2

c = 6 × a + 6 + 2

a + 3 × a + 3 + 6 × a + 6 + 2 = 111

10 × a + 3 + 6 + 2 = 111

10 × a + 3 + 6 = 111 - 2

10 × a + 3 + 6 = 109

10 × a + 3 = 109 - 6

10 × a + 3 = 103

10 × a = 103 - 3

10 × a = 100

a = 100 : 10

a = 10

b = 3 × 10 + 3 = 30 + 3 = 33

c = 6 × 10 + 6 + 2 = 60 + 6 + 2 = 66 + 2 = 68