Question

Determina-l pe X din: b) 169+5x{32:8+5x[40+8x(200:X-72:2)]}=1989

Answer 1

169+5*{4+5*[40+8*(200:x-36)]} = 1989
5*{4+5*[40+8*(200:x-36)]} = 1989-169
5*{4+5*[40+8*(200;x-36)]} = 1820
4+5*[40+8*(200:x-36)] = 1820:5
4+5*[40+8*(200:x-36)] = 364
5*[40+8*(200:x-36)] = 364-4
5*{40+8*(200:x-36)] = 360
40+8*(200:x-36) = 360:5
40+8*(200:x-36) = 72
8*(200:x-36) = 72-40
8*(200:x-36) = 32
200:x-36 = 32:8
200:x-36 = 4
200:x = 4+36
200:x = 40
x = 200:40
x = 5