Question

determina masurile a doua unghiuri suplementare,care sunt, i nvers proportionae cu 0,(3) ,respectiv 0,(6)

Answer 1

0,(3)= 3/9=1/3

0,(6)= 6/9=2/3

a,b   ip cu  1/3 ; 2/3

a/3= 2b/3=k

a=3k
b=3k/2

a+b=180

3k+3k/2=180  aducem la acelasi numitor

6k+3k=360
9k=360
k=40

a=3*40=120
b=3*40/2=3*20=60