Question

Determina valoarea fiecarei litere stiind ca :
a+b+c= 1 171
a+x= 401 ;
b+x= 549;
c+x= 680.

Answer 1

a+b+c=1171
a+x=401    a=401-x
b+x=549    b=549-x
c+x=680    c=680-x
(401-x)+(549-x)+(680-x)=1171
401+549+680-3x=1171
1630-3x=1171
1630-1171-3x=0
459=3x
x=459/3
x=153
a=401-153=248
b=549-153=396
c=680-153=527

Answer 2

a+x=401=>a=401-x; b+x=549=>b=549-x; c+x=680=>c=680-x; a+b+c=1171=>401-x+549-x+680-x=1171<=>1630-3x=1171=>3x=459=>x=153=>a=248;b=396;c=527