Question

Determina x din egalitatea; {[( a -8) x 7 + 6-5 ] - 4} x 3-2= 10 VA ROOOG !

Answer 1

{[( a -8) x 7 + 6-5 ] - 4} x 3-2= 10
{[( a -8) x 7 + 6-5 ] - 4} x 3= 10+2
{[( a -8) x 7 + 6-5 ] - 4} x 3= 12
[( a -8) x 7 + 6-5 ] - 4 = 12:3
[( a -8) x 7 + 6-5 ] - 4 = 4
( a -8) x 7 + 6-5 = 4+4
( a -8) x 7 + 6-5 = 8
( a -8) x 7 + 6 = 8+5
( a -8) x 7 + 6 = 13
( a -8) x 7 = 13-6
( a -8) x 7 = 7
a -8 = 7:7
a -8 = 1
a=1+8
a=9

Answer 2

{[(a-8)x7+6-5]-4}x3-2=10
{[(a-8)x7+6-5]-4}x3=10+2
{[(a-8)x7+6-5]-4}x3=12
[(a-8)x7+6-5]-4=12:3
[(a-8)x7+6-5]-4=4
(a-8)x7+6-5=4+4
(a-8)x7+1=8-1
(a-8)x7=7
a-8=7:7
a-8=1
a=8+1
a=9