Question

determinat functia de gradul al 2 lea fir=R f(x)=ax^+bx+c stiind caA(0,1)B(2,-3)C(-3,-3)

Answer 1

Răspuns:

Explicație pas cu pas:

f(x) = ax^2 + bx + c

f(0) = 1

f(2) = -3

f(-3) = -3

f(0) = a*0 + b*0 + c = 1

c = 1

f(2) = 4a + 2b + 1 = -3

4a + 2b = -4

2a + b = -2

b = -2a - 2

--------

f(-3) = 9a - 3b + 1 = -3

9a - 3(-2a - 2) + 1 = -3

9a + 6a + 6 + 1 = -3

15a + 7 = -3

15a = -3 - 7 = -10

a = -10/15 = -2/3

b = -2a - 2 = 4/3 - 2 = 4/3 - 6/3 = -2/3

f(x) = -2x^2/3 -2x/3 + 1