Question

Determinati 4 numere naturale consecutive pare consecutive,stiind ca media lor aritmetica este 39
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Answer 1

Notam numerele cu : a, a+2 , a+2 , a+2 a+a+2+a+2+a+2 (supra) 4 =39=> 4a+6= 39x4=> 4a+6=156=> 4a=150=> a=38 Numerele sunt: 38,40,42,44

Answer 2

(a+b+c+d):4=39
a+b+c+d=39x4
a+b+c+d=156 (suma celor 4 nr)
a+a+2+a+4+a+6=156
4a+12=156
4a=156-12
4a=144
a=36 (primul nr)
36+2=38 (II nr)
36+4=40 (III nr)
36+6=42(IV nr)