Question

Determinati a pentru care vectorii u=(a-2)i+3j si v=8i-(2-2a)j sunt coliniari

Answer 1

[tex] \frac{x1}{x2} = \frac{y1}{y2} \\ \\ \frac{a-2}{8}= \frac{3}{-2+2a} \\ \\ (a-2)(-2+2a)=24 \\ \\ -2a+2a^2+4-4a=24 \\ \\ 2a^2-6a-20=0/:2 \\ \\ a^2-3a-10=0
  rezolvi. ecuatia. si. afli .a [/tex]