Question

Determinati aria unui triunghi dreptunghic isoscel care are:
a) o cateta de 20 cm
b) ipotenuza de 14cm
c) perimetrul egal cu 12+6radical din 2

Answer 1

a) A=C1xC2\2
Δ isoscel C1=C2=20 cm
A=20x20\2=200 cm ²

b) ip=14
ip²=C1²+C2²=2C1²
14²=2C1²
196=2C1²
C1²=196\2=98
C1=7√2
C1=C2=7√2
A=7√2x7√2\2=98\2=49 cm²

c)P=12+6√2
P=ip+C1+C2
12+6√2=2C1+ip
6+6+6√2=C1+C1+ip
C1=6
A=6x2\2=36\2=18 cm ²