Question

Determinati c.m.m.d.c.al numerelor:
a=9×3×5^2-3^3
b=3^3×3^2-9^2

Answer 1

$a=9*3*5^2-3^3=3^2*3*5^2-3^3=3^3*5^2-3^3=648=2^3*3^4 ;;;; b=3^3*3^2-9^2=3^5-(3^2)^2=3^5-3^4=3^4(3-1)=3^4*2 ;;;; (a,b)=3^4*2=162$