Question

determinati care dintre urmatoarele numere este mai mare:A=(25^3)^9:(4^2+3^2)^26-(2017^0+0^2017+12017)^4 si B=2^7-11•{91-5•[22-5•(40^2-41•39)]}+(3^2-2^3)^2017

Answer 1

A = (25^3)^9:(4^2+3^2)^26-(2017^0+0^2017+12017)^
=25^27:(16+5)^26-(1+0+12017)^4
=25^27:25^26-12018^4
=25-12018^4

B = 2^7-11•{91-5•[22-5•(40^2-41•39)]}+(3^2-2^3)^2017
=128-11{91-5[22-5(40^2-1599)]}+(9-8)^2017
=128-11[91-5(22-5•40^2+7995)]+1^2017
=128-11[91-5(8017-5•40^2)]+1
=128-11(91-40085+25•40^2)+1
=128-11(-39994+25•40^2)+1
=128+439934-275•40^2+1
=440063-275•1600
=440063-440000
=63

Deci, A > B

Sper că te-am ajutat ^^