Question

determinati cel mai mic numar natural care impartit pe rand la 12 15 si 27 da de fiecare data restul 3 si caturi nenule

Answer 1

x:12=c1 rest 3
x=M₁₂+3

x:15=c2 rest 3
x=M₁₅+3

x:27=c3 rest 3
x=M₂₇+3

x=[12;15;27]+3
x-cel mai mic

12=2² *3
15=3*5
27=3³

[12;15;27]=3³ * 5 * 2²= 27 * 5*4= 27*20= 540

x=540+3=543