Question

Determinati cel mai mic numar natural diferit de zero care impartit la 12, 28 si, respectiv, 36 da de fiecare data restul 7.

Answer 1

x/12 =c1  r  7
x/28 =c2  r  7
x/36 =c2  r  7   (c1,c2,c3 =  cele 3 caturi )
x=12c1+7
x=28c2+7
x=36c3+7
12=2^2*3
28=2^2*7
36=2^2*3^2
cmmmc -2^2*3^2*7 =4*9*7 =252
252+7 /12 =21  r  7
252+7 /28 =9  r  7
252+7 /36 =7  r 7