Question

Determinati cel mai mic numar natural diferit de zero care impartit la 9 da restul 8,impartit la 6 da restul 5 si impartit la 3 da restul 2.Va multumesc anticipat

Answer 1

x:9=c1 rest 8=>x=9c1+8|+1=>x+1=9(c1+1) x:6=c2 rest 5=>x=6c2+5|+1=>x+1=6(c2+1) x:3=c3 rest 2=>x=3c3+2|+1=>x+1=3(c3+1) =>x+1=[9;6;3]=>x+1=18=>x=17