Question

determinati concentratia molara a solutiilor care contin: 400g NaOH in 5L solutie

Answer 1

Cred ca trebuia concentratia molara a solutiei*

$n= \frac{m}{M}= \frac{400}{40}=10$ moli NaOH

$c_{M} = \frac{n}{V_{s}}$ = $\frac{10}{5} = 2M$ ( sau 2 moli / L )