Question

determinati inaltimea unui paralelipipeddreptunghic care are L=50 dm,l=0,02 si volumul egal cu 60 m³

Answer 1

L=50 dm=5 m
l=0,02 hm=2 m
h=inaltimea
V=Lxlxh
5x2xh=60
10h=60
h=60:10
h=6 m

Answer 2

50dm=5m, 0.02hm=2m

V=60=L*l*h=5*2*h=>h=60/10=6m