Question

determinati media aritmetica a nr nat pozitive x y z stiind ca x si y sunt durect proportionale cu 4 si 6 si c si y sunt direct proportionale cu 8 si 12

Answer 1

X/4=Y/6
C/8=Y/12 ,║:2
⇒X/2=Y/6=Z/4=K⇒x=2k,y=6k,z=4k
⇔Ma=(x+y+z):3k=(2k+6k+4k):3k=12k/3k=4