Question

determinati nr naturalstiind ca a<b<c si 9*a+9*b+9*c=72.am nevoie urgent va rog

Answer 1

$a < b < c$

$9a + 9b + 9c = 72$

$9(a + b + c) = 72 \: | \div 9$

$a + b + c = 8$

$0 + 1 + 7 = 8$

$0 < 1 < 7$

$0+2+6=8$

$0<2<6$

$0+3+5=8$

$0<3<5$

$1 + 2 + 5 = 8$

$1 < 2 < 5$

$1 + 3 + 4 = 8$

$1 < 3 < 4$