Question

determinati nr x y si z invers proportionale cu numerele 5 6 si 15 stiind ca 3x-2y-z=12

Answer 1

x/5 = y/6 = z/12 = k

x/5=k   x=5k

y/6=k    y=6

z/15 =k   z=15

3*5k - 2*6k -15k =12

k*(15-12-15) = 12

-12 k =12

k = -1

x = 5*(-1)= -5

y = 6*(-1)= -6

z = 15*(-1)= -15