Question

Determinati numarul a din egalitatea:[940+5x(12+a)-1785]:3+5=410
Ajutatima va rog !!

Answer 1

[940+5x(12+a)-1785]:3+5=410

(12+a) o sa o notam cu t

(940+5xt-1785):3=410-5

(940+5t-1785):3=405

940+5t-1785=405x3

940+5t-1785=1215

940+5t=1215+1785

940+5t=3000

5t=3000-940

5t=2060=>t=2060:5=>t=412

sa nu uitam ca noi am notat t ca fiind12+a

deci 12+a=412=> a=412-12=> a=400

verificam

[940+5x(12+400)-1785]:3+5=(940+5x412-1785):3+5=(940+2060-1785):3+5=(3000-1785):3+5=1215:3+5=405+5=410 (deci adevarat)