Question

Determinati numarul de Atomi de Natriu care se gasesc in 288gr. de NaCo3

Answer 1

sarea se scrie Na2CO3
miu(M)=(2X23gNa+12gC+3x16gO)/mol=106g/mol

niu,mol= m/miu;   niu= 288g/106g/mol=2,7mol
1mol sare..........2molatomi Na
2,7mol.................n=5,4mol atomiNa

1mol atomi....are.....6,023x10²³atomi
5,4mol......................N= 5,4x6,023x10²³atomi=....................calculeaza !!!!!